1. The problem statement, all variables and given/known data Given this one period graph of a function with period 2pi, find a fourier expansion. 2. Relevant equations 3. The attempt at a solution So I was wondering if i can split up the integrals into two parts to find the coefficients. It is an even function so ak = 0. for bk can I split the integral as follows 1/pi[int 0 to pi (x cos kx dx) + int pi to 2pi ((-x+2pi) cos kx dx] ?