Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Chemistry
Biology and Medical
Earth Sciences
Computer Science
Computing and Technology
DIY Projects
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Chemistry
Biology and Medical
Earth Sciences
Computer Science
Computing and Technology
DIY Projects
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Other Sciences
Chemistry
How to assign symmetry to water molecule using D4h symmetry?
Reply to thread
Message
[QUOTE="fangrz, post: 5469674, member: 542277"] Could you explain why an H2O that attacks Ni(CN)4 ^(2-) (in square planar) (which has D4h symmetry) at one of the axial sites would have A2u symmetry? I know that the "HOMO" for the p orbital of the H2O would be a p orbital. I also tried to link that electron pair to an irreducible representation in the D4h character table. Going across the row: E 2C4 (z) C2 2C'2 2C''2 i 2S4 σh 2σv 2σd I got the following numbers: +1, +1, +1, 0, 0, 0, 0, 0, +1, +1...which doesn't correspond with any of the irreducible representations. (When the H2O flips because of a C2' or C2'' rotation (and others...), it gives 0s. Was there something wrong in my approach? I used the metal center as the center for all operations. [/QUOTE]
Insert quotes…
Post reply
Forums
Other Sciences
Chemistry
How to assign symmetry to water molecule using D4h symmetry?
Back
Top