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How to break the fracture

  1. Aug 16, 2009 #1
    [tex]\frac{1}{x^3(x^2+1)}=\frac{ax^2+bx+c}{x^3}+\frac{dx+e}{x^2}\\[/tex]
    [tex]ax^4+bx^3+cx^2+dx^4+ex^3=x^4(a+d)+x^3(b+e)+cx^2=1\\[/tex]
    [tex]c=0\\[/tex]
    [tex]b+e=0\\[/tex]
    [tex]a+d=0\\[/tex]

    i got 4 variables with 2 equations

    what to do??
     
  2. jcsd
  3. Aug 16, 2009 #2
    [tex]\frac{1}{x^3(x^2+1)}=\frac{ax^2+bx+c}{x^3}+\frac{dx+e}{x^2+1}\\[/tex]
     
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