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How to calculate interaural phase difference and interaural time difference ?

  1. Feb 19, 2009 #1
    How to calculate interaural phase difference and interaural time difference ???

    Here is what I am given:
    A sound reaches one ear with a mean phase of 338 degrees and vector strength of 0.67
    It reaches the other ear with a phase of 294 degrees and vector strength of 0.60

    The sound frequency is 4409 hz.

    I need to find out what is the best interaural phase difference and interaural time difference of the neuron that is being looked at.



    I'd also love it if someone could explain the recurring peaks shown in this plot:
    phasediff.jpg

    Also, what would the above curve look like if a frequency of 5102hz was used instead? (assume the neuron responds equally well to each frequency)


    Lastly, (I don't even understand what this question is asking, so the more explanation you could give, the better...) let's assume the above figure has a best frequency of 4409hz. Draw the ITD curve that you'd expect from using a broadband stimulus in which all frequencies within the audible range of the owl were present (hint: the basilar membrane acts like a Fourier transformer.) Draw the ITD curve that would result if the positive and negative terminals of the inputs to the headphone on the right side were reversed. Label your diagram clearly to indicate the consequences. This polarity reversal will invert the sine wave by 180 degrees in the right headphone.

    I have no idea what is going on with any of this and just need to get through this question... so any help you could offer would be AWESOME!

    Thanks in advance...
     
  2. jcsd
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