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f(x,y)=e^-(2x^2+2y^2) but I do not know where to start. Any advice on first steps would be greatly appreciated.

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- Thread starter cue928
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- #1

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f(x,y)=e^-(2x^2+2y^2) but I do not know where to start. Any advice on first steps would be greatly appreciated.

- #2

SammyS

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Once you do that, see if you can come up with a more general solution.

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HallsofIvy

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