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How to calculate ω

  1. Jun 18, 2013 #1
    1. The problem statement, all variables and given/known data
    A mechanical system consists of body 1, having mass m1 = 54 kg, a two-stage disc 2, having mass m2 = 24 kg and radii R = 0.6 m and i = R/4 (i is the radius of inertia about the central axis, perpendicular to the disc), and two equal horizontal linear springs, each of the of a coefficient of elasticity c = 1092 N/m. A non-elastic cord of negligible mass rolled over the small stage connects the disc with body 1. The disc moves without sliding over a horizontal plane. At the initial instant body 1 is shifted down at x0 = 0.07 m and released without initial velocity. Assuming the system makes small oscillations around its equilibrium, find the differential equation of the system motion (using axis x), find the motion law x(t) and determine the natural frequency as well as the period of these oscillations. (I have attached a picture of the system)



    2. Question
    I don't want the solution to the whole problem, I just wanted to ask if someone could explain to me how do we take the value of ω2 with respect to the velocity of body 1, with respect to the velocity of point B and C as well. I have the equations, but I don't understand them.
    In the book is written:
    ω2 = V1 / (R - R/2) = 2V1 / R (why do we subtract the 2 radii)
    Vc = ω2*R = 2V1 (why do we multiply by the radius of the big disc)
    Vb = ω2*(3R/2) = 3V1 (why do we add the 2 radii)
    where V1 is used as the first derivative of x (x with a point on top of it).

    Since both, the cord and spring 2 are connected to the smaller disc, shouldn't their velocities be the same?



     

    Attached Files:

    Last edited: Jun 18, 2013
  2. jcsd
  3. Jun 18, 2013 #2
    The disk is said to roll without sliding. Where is the axis of rotation then?
     
  4. Jun 18, 2013 #3
    I'm sorry I couldn't draw it, but it's at point C
     
  5. Jun 18, 2013 #4
    What is the velocity of the disk at the point where it touches the plane?
     
  6. Jun 18, 2013 #5
    Does that matter, because I don't know?
     
  7. Jun 18, 2013 #6
    What does rolling without sliding mean to you?
     
  8. Jun 18, 2013 #7
    Am.. exactly what it says, that the disc rolls, but doesn't slide. I know I have gaps in my knowledge, but my teacher is not a very good one.
     
  9. Jun 18, 2013 #8
    What is sliding then?
     
  10. Jun 18, 2013 #9
    To move over a surface while maintaining smooth continuous contact.
     
  11. Jun 19, 2013 #10
    Well, that is a nice definition, but it does not define anything. A ball rolling will satisfy it just as well.

    Sliding really means that the points of contact of a body with a surface have a non-zero velocity with regard to the surface.

    Rolling without sliding (or slipping) means that the point of contact has zero velocity. This is why rolling something (that can be rolled) is so much easier than dragging it - you don't have to overcome friction.

    Now back to the problem. If the point of contact has zero velocity, where is the axis of rotation?
     
  12. Jun 19, 2013 #11
    Well, it should be through point C
     
  13. Jun 19, 2013 #12
    I do not know what your "should be" means. The question is where it is.
     
  14. Jun 19, 2013 #13
    OK, you know what, never mind, I actually managed to answer my question. Thanks for the help.
     
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