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A How to calculate the energy of Gamma rays in fusion

  1. Nov 22, 2017 #21

    mfb

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    Unless you shoot the two protons together in accelerators, you don’t have this initial 1.25 MeV around. The diproton has to be off-shell, and the total energy released is just 420 keV as required by conservation of energy (add a fee keV from the thermal energy of the protons). As this is smaller than the electron mass most of the energy goes into the neutrino (on average).
    Here is a plot, the peak is somewhere around 300 keV.
     
  2. Nov 22, 2017 #22
    I see there is some probability distribution from which the peak is around 300 keV and it can go up to almost 420 keV. Does this also mean on average its energy is about 300 keV as well?
     
  3. Nov 22, 2017 #23

    mfb

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    We would have to integrate the distribution to get the average, but it should be something between 250 to 300 keV.
     
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