(adsbygoogle = window.adsbygoogle || []).push({}); The problem that was given:

[tex]{\frac {d}{dx}}y \left( x \right) =2\,{\frac {x}{{x}^{2}\cos \left( y

\right) +4\,\sin \left( 2\,y \right) }}

[/tex] after doing some changes we get a bernuli that looks like this

[tex]2\, \left( {\frac {d}{dy}}x \left( y \right) \right) x \left( y

\right) =\cos \left( y \right) \left( x \left( y \right) \right) ^{

2}+4\,\sin \left( 2\,y \right)[/tex]

with the initial conditions that x=f(y) goes through (1,0) (1=x,0=y)

the solution is

[tex]\left( x \left( y \right) \right) ^{2}=-8-8\,\sin \left( y \right) +

9\,{{\rm e}^{\sin \left( y \right) }}[/tex]

for these conditions the boundry is Dy=(arcsin(ln(8/9)),pi/2) which includes the point in the initial conditions the only problem i have is i dont know how to choose the final solution for x(y) thus whether is it th possitive root or the negative one

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# How to decide right solution

Loading...

Similar Threads for decide right solution | Date |
---|---|

I How to find a solution to this linear ODE? | Feb 21, 2018 |

Integral relation with ## U \left[a,1,z \right] ## | Jan 6, 2016 |

N body solver (is this right?) | Sep 9, 2014 |

This is a mistake right? | Oct 1, 2013 |

How does dy/dt=ry end up with the constant multiple on the right? | Sep 11, 2013 |

**Physics Forums - The Fusion of Science and Community**