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How to determine number of dark fringes by a single slit with only lamba and width

  1. Jan 22, 2007 #1
    1. How many dark fringes will be produced on either side of the central maximum if light ( = 553 nm) is incident on a single slit that is 5.1 10-6 m wide?



    2. sin theta = m (lamba/ W)

    lamba = wavelength
    W = slit width
    m - number of fringes




    3. I have no idea how to do this without at least an L or theta.

    Does anyone know what I am to do?
     
  2. jcsd
  3. Jan 22, 2007 #2
    ok, i decided to try the slit width divided by the wavelength. This gave me the correct answer.

    Is this because this is a way to determine how many wavelengths will fit through the slit and therefore how many fringes there will be?

    I just want to make sure I am using a correct theory here and that I did not just get lucky.
     
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