1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How to find a wave eqation?

  1. Nov 21, 2012 #1
    in the form
    y(x,t)=Asin(k(x-vt)+δ)
    where p is the phase angle

    A is .02m
    v=22.4m/s
    t=0.1s
    k=2.80
    wavelengh= 2.24m
    at time t=0, the dispaclement(y) is 0.01m with dy/dt is negative

    Im not sure how to findδ
     
  2. jcsd
  3. Nov 22, 2012 #2

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    You'll find there are a couple of bits of information you have not used yet.
     
  4. Nov 22, 2012 #3
    I was just having the biggest brain fart ever, I figured it out after I posted, but didnt have a chance till now to comment
     
  5. Nov 22, 2012 #4

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    No worries - sometimes asking a question can be just the thing to unstick the grey matter.
    How about posting your answer so anyone else with the same problem will see how you did it?
     
  6. Nov 22, 2012 #5
    ok well the wave equation is


    y(x,t)=Asin(k(x-vt)+δ)
    we know A, v,and k and we can sub them in to get
    y(x,t)=0.02sin(2.8(x-22.4t)+δ)
    and expand
    y(x,t)=0.02sin(2.8x-62.8t+δ)

    to get δ we take the conditions given @t=0, y=.01m
    x=0m( its at the driving end, I left this out in my initial question)
    now solving for δ we get δ=0.52
    therefore
    y(x,t)=0.02sin(2.8x-62.8t+0.52)
     
  7. Nov 22, 2012 #6

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Bootiful :) cheers!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook