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How to find angle of a curve in xy coordinate plane?

  1. Aug 14, 2003 #1
    Hi,

    I think it is atan of the derivative of the curve, is that right?

    Thanks

    Matt
     
  2. jcsd
  3. Aug 14, 2003 #2

    mathman

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    The derivative is the slope of the tangent line. The atan is thus the angle of the tangent line with the x axis.
     
  4. Aug 14, 2003 #3
    Thanks for the quick reply. Yeah, that is what I thought. However, I have a followup question.

    For the vertical position of a projectile the formula is:

    y = initialheight + VyT - .5(9.8)T^2

    The derivative of that is

    d/dx = Vy - 9.8T

    I did a sample problem, Vi=4, angle = 30º, initial height = 1.2

    Total Time: .739 seconds
    Height of Max time: .202 seconds
    Distance: 2.56 m

    if I take atan( Vy - 9.8T) when t = 0 the angle comes up as 63º, not 30º which it should be.

    Hmm?
     
    Last edited: Aug 14, 2003
  5. Aug 15, 2003 #4
    I started to work out the problem, but you didn't state it quite clearly....

    Do you mean V0x is the initial Vi in the direction of vector i ?
     
    Last edited: Aug 15, 2003
  6. Aug 15, 2003 #5

    HallsofIvy

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    dy/dx is the arctan of the angle the curve makes with the horizontal.

    dy/dt has no geometric meaning (in an xy-coordinate system).

    If Vi= 4 is the initial speed and the projectile is fired at a 30 degree angle to the horizontal, then the initial vertical speed is Vy= 4 cos(30)= 4(1/2)= 2 and the initial horizontal speed is
    Vx= 4 sin(30)= 4([sqrt](3)/2)= 2 [sqrt](3).

    The vertical speed would be given by dy/dt= 2- 9.8t and the horizontal speed (assuming gravity is the only force) by
    dx/dt= 2[sqrt]3. At t= 0, dy/dt= 2 and dx/dt= 2[sqrt](3).
    By the chain rule, dy/dx= (dy/dt)/(dx/dt)= 2/2[sqrt](3)= 1/[sqrt](3)= [sqrt](3)/3, the tangent of 30 degrees.
     
  7. Aug 15, 2003 #6
    Thanks, Hallsofivy. You created a good thorough reply. However, I think you accidentally swapped cosine and sine in Vx and Vy.

    Anyway, for the benifit of searches, here is the formula for the angle:

    [​IMG]
     
    Last edited: Aug 15, 2003
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