conov3 said:Homework Statement
Two conducting spheres are connected by a thin wire and are in electrostatic equilibrium. The diameter of the smaller sphere is 2.0 cm and the diameter of the larger one is 9.0 cm. If the smaller sphere is found to be charged to 3.0 nC, what is the charge of the larger sphere?
Homework Equations
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The Attempt at a Solution
2/3=9/x
x=13.5nC? Am i able to use this rule to find the charge
The charge of a sphere can be determined by calculating the electric field at the surface of the sphere and multiplying it by the surface area of the sphere.
The equation for finding the charge of a sphere is Q = 4πε0r2E, where Q is the charge, ε0 is the permittivity of free space, r is the radius of the sphere, and E is the electric field at the surface of the sphere.
Yes, the charge of a sphere can be negative. This means that the sphere has an excess of electrons, giving it a negative charge.
The charge of a sphere directly affects the strength of its electric field. A greater charge will result in a stronger electric field, while a smaller charge will result in a weaker electric field.
Yes, the charge of a sphere can change. This can occur through the transfer of electrons, also known as charge transport, or through the application of an external electric field.