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How to find critical points for a differential equation?
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[QUOTE="epenguin, post: 4518981, member: 106258"] Spell things out a little more carefully. What you quote a solution for I think is really saying ∂f/∂x = 0 at all points along (x/y)[SUP]2[/SUP] = those numbers, which is actually [I]four lines [/I]through the origin I think. Maybe there is a nice algebraic breakup of your ∂f/∂y but anyway what you are doing should lead you to the four points along the four lines. Alternative approach is to find (dy/dx)[SUB]f[/SUB] and its reciprocal and find the points where both are 0. Well same thing really, -(dy/dx)[SUB]f[/SUB] is the ratio of your two derived polynomials. Also I think the second of yours, what you call "dy" is mistaken and it works out fairly simply. You might as well have taken the factor 3 out of your starting equation. [/QUOTE]
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How to find critical points for a differential equation?
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