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How to find distance

  1. Oct 6, 2008 #1
    sorry, i meant how to find TIME.

    1. The problem statement, all variables and given/known data
    A baseball is seen to pass upward by a window 25 m above the street with a vertical speed of 13 m/s. The ball was thrown from the street. I figured out the altitude thrown was 33.62 and the initial velocity was 25.67.

    (a) How long after it was thrown did it pass the window?

    (b) After how many more seconds does it reach the street again?

    2. Relevant equations
    the 4 kinematic equations

    For example, v^2=v0^2+2a(x-x0)

    3. The attempt at a solution
    I tried V=V0+at
    and and got 2.6 for part a and have no clue how to do part b. can someone help me out?
  2. jcsd
  3. Oct 6, 2008 #2


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    Staff Emeritus
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    Gold Member

    Not sure how you arrived at 2.6 for part a. I'd check that.

    For part b, you know that the final vertical distance is zero and you have worked out the initial velocity. Which kinematic equation has distance initial velocity and time in it?
  4. Oct 6, 2008 #3
    correct me if im wrong d1=d0+vt+(1/2)a(t2)

    that's all you need isn't it?
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