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How to find Final Speed.

  1. Nov 5, 2013 #1
    A steel ball is launched at 25 degrees above horizontal from the top of a platform that is 15 meters above ground. If the initial speed is 10m/sec, what is the final speed when it strikes the ground?
     
  2. jcsd
  3. Nov 5, 2013 #2

    tiny-tim

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    hi rqu1ntana! welcome to pf! :wink:

    show us what you've tried and where you're stuck, and then we'll know how to help! :smile:

    (use the standard constant acceleration equations, in the x and y directions separately)
     
  4. Nov 5, 2013 #3
    The problem is that its for a test and i just want to be sure what i did was right. This is what i did,

    I used the formula Vf2=Vi2-2g(y-yi), where Vi2 is the initial velocity, g is gravity=9.8, y is 0, and yi is the height.

    from all the data given this is what it looks like, Vf=(102-(2*9.8*(-15)))1/2

    The result i get from this is 13.56m/sec, i this right?
     
  5. Nov 5, 2013 #4

    tiny-tim

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    hi rqu1ntana! :smile:
    yes that looks fine :smile: … you've used conservation of energy (so the 25° doesn't matter)

    except that you keyed in -110 instead of 100 ! :redface:
     
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