- #1
amcavoy
- 665
- 0
I already know the answer to this, but would like your opinion on the quickest way to calculate integrals like these. I am finding myself evaluating similar integrals in my differential equation homework, and the method that I used (parts and partial fractions) is a mess and takes way too long (if it were to appear on a test).
[tex]\int\left(\frac{1-x}{x^2-4}\right)dx[/tex]
Thanks.
[tex]\int\left(\frac{1-x}{x^2-4}\right)dx[/tex]
Thanks.