- #1

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- Thread starter Sneakatone
- Start date

- #1

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- #2

- 644

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- #3

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I used the same equation and had 2.3 s and had 19.56 m/s. is that process correct?

- #4

- 36,993

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I make it 2.47s. Pls show your working.I used the same equation and had 2.3 s and had 19.56 m/s. is that process correct?

I can't do part b because I don't know the layout of a baseball pitch. In fact, I don't understand how you're supposed to know which direction the ball went.

I note also that the question makes no allowance for the height off the ground when the ball was struck.

- #5

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so I do 38 meters/ 2.47 seconds= 15.38 m/s .?

- #6

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It's called a field or a diamond. A pitch in baseball is the throw the pitcher makes at the batter.I make it 2.47s. Pls show your working.

I can't do part b because I don't know the layout of a baseball pitch.

I think we are to assume that ball goes straight at the center fielder.In fact, I don't understand how you're supposed to know which direction the ball went.

I think we are to assume it is to be caught at the same height it was hit from.I note also that the question makes no allowance for the height off the ground when the ball was struck.

- #7

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I still dont understand what to do

- #8

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First, a correction. I don't get 2.47s for the flight time of the ball, I get 6.10s. Sneakatone, if you do not get that pls post your working. If/when you have the flight time right, find where the ball will land (as tms already instructed).I still dont understand what to do

- #9

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I did 0=38cos(52)+(9.8)t

45/6.1= 7.4 m/s

would that be correct?

45/6.1= 7.4 m/s

would that be correct?

- #10

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Why did you do that? You seem to be mixing up the horizontal and vertical components, among other things. Try using symbols to set up your equations; it will be clearer what is going on and where you are going wrong. It is best to proceed systematically. Start by drawing a diagram showing the forces on the ball. Then write down the kinematic equation for the vertical direction, then solve it for the time taken to go up and down.I did 0=38cos(52)+(9.8)t

- #11

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- #12

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And the distance the fielder is from the batter has no influence on the ball's trajectory.

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