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Apollinaria
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I will keep working on this while waiting for someone here to respond...
A ball m= 0.0024kg is electrically charged when 1E11 electrons are added. The ball falls with a=3.13m/s2 in an electric field. Find magnitude and direction of field.
q= Ne
If the ball is falling in the elec. field, it means it has a positive charge. If it's falling, it's going down so I have my direction for the elec. field.
I'm guessing that the charge on it is the number of electrons added * charge of electron.
So, 1E11 x (1.60E-19)= 1.6E-8 charge on ball.
F= qE. I don't have E. E=kq/r2, I don't have r.
And now?...
Homework Statement
A ball m= 0.0024kg is electrically charged when 1E11 electrons are added. The ball falls with a=3.13m/s2 in an electric field. Find magnitude and direction of field.
Homework Equations
q= Ne
The Attempt at a Solution
If the ball is falling in the elec. field, it means it has a positive charge. If it's falling, it's going down so I have my direction for the elec. field.
I'm guessing that the charge on it is the number of electrons added * charge of electron.
So, 1E11 x (1.60E-19)= 1.6E-8 charge on ball.
F= qE. I don't have E. E=kq/r2, I don't have r.
And now?...
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