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How to find this limit?

  1. Dec 10, 2008 #1
    closed.
     
    Last edited: Dec 10, 2008
  2. jcsd
  3. Dec 10, 2008 #2
    Within a set of parentheses, you will have

    1+x+x^2. The limit of this as x--> 0 is 1.

    You then have

    ((1)^(1/x)-e)

    One to any power is still one, so

    1-e
     
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