# How to find this limit?

1. Dec 10, 2008

### helpme7

closed.

Last edited: Dec 10, 2008
2. Dec 10, 2008

### flatmaster

Within a set of parentheses, you will have

1+x+x^2. The limit of this as x--> 0 is 1.

You then have

((1)^(1/x)-e)

One to any power is still one, so

1-e