How to find W/L?? 1. The problem statement, all variables and given/known data The exercise already tells me that the value of W/L is 2. However, I can't seem to understand where that result came from. I'd like to know how I can get to that conclusion. Here is the exercise with the graph of the inverter: Inverter image: http://i1226.photobucket.com/albums/ee410/jean28x/image2_zps9e7f8724.png Exercise, part 1: http://i1226.photobucket.com/albums/ee410/jean28x/image_zps136b69f7.png Exercise, part 2: http://i1226.photobucket.com/albums/ee410/jean28x/image_1_zps32b9a8ee.png 2. Relevant equations Here is a picture of relevant formulas of MOSFETS: http://i1226.photobucket.com/albums/ee410/jean28x/image_2_zpse3d8245e.png There is also the formula in the hint that is given in the exercise: http://i1226.photobucket.com/albums/ee410/jean28x/image_1_zps32b9a8ee.png 3. The attempt at a solution So, using the formula given in the hint, I substitute the values (I already know the 48 KΩ part): 48k = 1/((125μ)(W/L)(2.5 - 0.5)) Solving for W/L, I get: 12 = 1 / (W/L) W/L = 1 / 12 = 0.08333 However, the answer says that W/L is supposed to be 2. What am I doing wrong here??? Thanks a lot. P.S. It might be worth noting that, since this is an exercise working with CMOS circuits, then the relevant state that it should be analyzed in is in Triode and Cutoff modes.