- #1

Cafka

- 6

- 0

y'' + y = 2cosx - 3sinx

I know how to do everything except for get yp. I know it has to be something so when i substitute yp into the left hand side of the equation, i get the right hand side, 2cosx - 3sinx.

By this definition i would think yp = Acosx - Bsinx, where A = 2 and B = 3. But that doesn't seem right.

Can anyone help me out?

Thank you.