- #51

CAF123

Gold Member

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For example, we want, at say [itex] x = 3m, y [/itex] to be 15.50m. Here, my assumption is that 3m is the distance from the first wheel to the cannon. The only unknowns you have is [itex] v_o [/itex] and [itex] θ [/itex].

I then took another stage in the journey say, right at the end, where [itex] y = 2.50 m [/itex] and [itex] x [/itex] is about [itex] (10.63 +6) ≈ 17m [/itex]. Thus, I have two eqns and two unknowns which can be solved to yield some [itex] θ [/itex] and [itex] v_o [/itex].

Is this method plausible? Of course, after getting some result, to get minimal velocity, you could tweak the distance from the cannon to the first wheel and see what happens.