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Calculus and Beyond Homework Help
How to get the integral result?
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[QUOTE="Ray Vickson, post: 6001748, member: 330118"] In questions of this type you should [B]always[/B] try to simplify first, before doing anything else. So if we use the notation ##w## instead of your ##\Delta## and ##a## instead of your ##t/2##, we have an integral of the form $$I(a) = \int_{-\infty}^{\infty} \frac{\sin^2(a w)}{w^2} \, dw.$$ Change variables to ##u = a w## to get ##I(a) = a K##, where $$K= \int_{-\infty}^{\infty} \frac{\sin^2 u}{u^2} \, du.$$ Now ##K## is just some constant; it happens to equal ##\pi##, but that is another issue. [/QUOTE]
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Calculus and Beyond Homework Help
How to get the integral result?
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