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It's my first time here so I guess I have to introduce myself first.

I am a junior in high school taking Calculus BC and Physics B (taking Physics C next year).

Currently, as of September 29, 2008, my class is learning of Polar equations.

We just went over basics but I am not perfectly grasping the concept on using polars.

One of the question I received during class was:

r=1/2 + sin([tex]\theta[/tex]

Now, without using calculator, how do I find the area of the equation which excludes the overlaping part.

I know that

A=1/2[tex]\int[/tex]r^2 d[tex]\theta[/tex]

but here we would subtract the inner area.

No point in using calculator;;; I cannot check my answer either since my teacher said the right answer choice is not shown (it is a multiple choice question).

ps. I don't know how to use the "tex" thing so...

I am a junior in high school taking Calculus BC and Physics B (taking Physics C next year).

Currently, as of September 29, 2008, my class is learning of Polar equations.

We just went over basics but I am not perfectly grasping the concept on using polars.

One of the question I received during class was:

r=1/2 + sin([tex]\theta[/tex]

Now, without using calculator, how do I find the area of the equation which excludes the overlaping part.

I know that

A=1/2[tex]\int[/tex]r^2 d[tex]\theta[/tex]

but here we would subtract the inner area.

No point in using calculator;;; I cannot check my answer either since my teacher said the right answer choice is not shown (it is a multiple choice question).

ps. I don't know how to use the "tex" thing so...

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