# How to incorporate the initial vellocity

I'm having difficulty with the following problem: What is the average force exerted by a shot-putter on a 7.0 kg shot if the shot is moved through a distance of 2.8 m and is released with a speed of 13 m/s.

I know that I have to use the formula F=ma. The mass is obviously 7.0 kg, but I don't know how to find the horizontal component of the acceleration of the shot. I don't know how to incorporate the initial vellocity and the distance the shot travels. I would appreciate any help. Thanks.

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jcsd
Gold Member
Use the formula:

v2 = u2 + 2as

Last edited:
what do the variables stand for?

jcsd
Gold Member
v is final velocity (13ms-1), u is initial velocity (assume this to be zero), a is accleration, s is displacement (distance).

ok, so that gives an acceleration of 2.32m/s^2. But it doesn't make sense that this would be the acceleration to plug into the formula F=ma. I know that the correct answer to the problem is 210 N.

jcsd