- #1
Prototype
- 6
- 0
(x) sq. root of ((x^2) - 1)?
Jameson said:That last step is a typo or it's incorrect.
It should be:
[tex]u = x^2-1[/tex]
[tex]du = 2x dx[/tex]
[tex]\frac{du}{2} = x dx[/tex]
Your end substitution is correct, with [tex]\frac{1}{2}\int\sqrt{u}du[/tex]
but that one step is off.
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