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How to prove

  1. Sep 10, 2008 #1
    How would someone go about proving:

    [tex]\Im (ln(-|x|))=\pi [/tex] for all reals, x, when the answer takes the form, a + bi.
  2. jcsd
  3. Sep 10, 2008 #2


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    What's wrong with direct calculation?
  4. Sep 11, 2008 #3


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    Negative real numbers can be expressed in polar coordinates as re(pi)i. Take the log and you get ln(r)+(pi)i.
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