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__Here is the problem__Find the volume of the region enclosed by the spherical coordinate surface [tex]\rho = 2 \sin\theta[/tex], using spherical coodinates for the limits of the integral.

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__Here is what I have__I don't know if this is right, but here it is [tex]\int_{0}^{2\pi}\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\int_{0}^{2\sin\theta}\;\rho^2\;\sin\theta\;d\rho\;d\phi\;d\theta[/tex]