- #1
aisha
- 584
- 0
[tex] 2-2\sin^2(\theta)=\cos (\theta) [/tex]
I need to solve this quadratic trig equation algebraically of the domain 0<=x<=2pi I know how to do that but in order to solve the trig functions have to be the same I'm having a little trouble how do I change the cos into sin? It's not cos^2 so we can't use the pythagorean identity.
I need to solve this quadratic trig equation algebraically of the domain 0<=x<=2pi I know how to do that but in order to solve the trig functions have to be the same I'm having a little trouble how do I change the cos into sin? It's not cos^2 so we can't use the pythagorean identity.