I tried to solve this differential equation:(adsbygoogle = window.adsbygoogle || []).push({});

2y+(y')^2+ax^b=0

...but don't know what to do with it.

Don't know what variable substitution to use.

Tried Taylor series, but I get horrible nonlinear equations for the coefficients.

Tried Mathematica, but it doesn't answer anything:

Can you help me?Code (Text):

In[20]:= Dsolve[2*y + y'^2 + a*x^b == 0, x]

Out[20]= Dsolve[a x^b + 2 y + (Derivative[1][y])^2 == 0, x]

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# I How to solve 2y+(y')^2+ax^b=0 ?

Tags:

Have something to add?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**