# How to solve dy/dx=3√(xy)

1. Mar 8, 2009

### rapwaydown

how to solve dy/dx=3√(xy) for a general solution?

PS: √ is square root sign, just in case if it is not clear.

Thank You

2. Mar 8, 2009

### csprof2000

That equation is separable. Let me explain.

dy/dx = 3/sqrt(xy)
<=>
dy/dx = 3/sqrt(x)sqrt(y)
<=>
sqrt(y)dy = [3/sqrt(x)]dx
<=>
(2/3)y^(3/2) = 6sqrt(x) + C
<=>
y^(3/2) = 9sqrt(x) + C
<=>
y = [9sqrt(x)+C]^(2/3)

I think that's right. Does that look ok?

Last edited: Mar 8, 2009
3. Mar 8, 2009

4. Mar 8, 2009

Nope.

5. Mar 8, 2009

### rapwaydown

because i have the answer key, and it said the answer for this quesiton should be y=[(x^(3/2)+c)]^2

Thank you alot.
im self learning Differential Equations, i really appreciate your help.

6. Mar 8, 2009

### K.J.Healey

you have to integrate both sides simultaneously.

7. Mar 8, 2009

### rapwaydown

yea, that is what the book suggest me to do, but i got stuck when trying to integrate both sides

8. Mar 8, 2009

### csprof2000

I accidentally did

dy/dx = 3 / sqrt(xy).

I'm surprised you didn't catch this. Oh well. Sorry for the confusion. Your problem is actually easier than the one I did.

dy/dx = 3sqrt(xy)
<=>
dy/sqrt(y) = 3sqrt(x)dx
<=>
2sqrt(y) = 2x^(3/2) + C
<=>
y = [x^(3/2)+C]^2

9. Mar 8, 2009

### rapwaydown

its ok. thanks alot csprof2000
im self learning this, so you will be surprise by how simple my questions are.
they are easy for you, but not esay for me.
im doing my best to get an overall knowledge of Differential Equations before i enter college.
thanks again csprof2000.
i have one question though, are you a teacher or professor?

10. Mar 8, 2009

### csprof2000

A professor, but thankfully not of anything as hard as this. They have me doing the introductory sequence, mostly...

11. Mar 8, 2009

### rapwaydown

this explain why i spend like about 2 hours on 3 questions, and still cant figure out any of them, but you spend like a few minutes and sloved one of the questions.
where do you teach?

12. Mar 9, 2009

### csprof2000

I'd rather not say, if that's alright. I like to maintain some anonymity in these forums, and I don't want any of my students figuring out whom I am.

But it's in the USA, in the South. A state university...