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How to solve this asymptotic equality?

  1. Jun 5, 2015 #1
    How do I solve for x in the relationship below:

    nx ~ n ln(n), as n -> infinity

    The answer that I'm getting is x=1, but that must be wrong since 1 ~ ln(n) as n-> infinity is wrong.
     
  2. jcsd
  3. Jun 5, 2015 #2

    pasmith

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    There is no solution: [tex]\frac{\ln n}{n^k} \to \begin{cases} 0 & k > 0 \\ \infty & k \leq 0 \end{cases}[/tex]
     
  4. Jun 5, 2015 #3
    oh boy
     
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