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How can I solve this inequality?
(a-x+1)(a-x+2) ≤ a
where a is a constant with unknown value.
Thanks in advance.
(a-x+1)(a-x+2) ≤ a
where a is a constant with unknown value.
Thanks in advance.
Brilliant. Thanks!If you want to find x in terms of a, I would start with
((a - x + 3/2) - 1/2)((a - x + 3/2) + 1/2) ≤ a
The left hand side is then the difference of two squares.....