- #1
nightking
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How can I solve this inequality?
(a-x+1)(a-x+2) ≤ a
where a is a constant with unknown value.
Thanks in advance.
(a-x+1)(a-x+2) ≤ a
where a is a constant with unknown value.
Thanks in advance.
AlephZero said:If you want to find x in terms of a, I would start with
((a - x + 3/2) - 1/2)((a - x + 3/2) + 1/2) ≤ a
The left hand side is then the difference of two squares...
An inequality is a mathematical statement that compares two quantities using inequality symbols such as <, >, ≤, or ≥. It shows that one quantity is greater or less than the other.
To solve an inequality, first determine the variable that you are solving for. Then, use algebraic techniques such as adding, subtracting, multiplying, or dividing both sides of the inequality to isolate the variable on one side. Finally, check the solution by plugging it back into the original inequality and making sure it is true.
In solving an equation, you are finding the value of the variable that makes both sides of the equation equal. In solving an inequality, you are finding the possible values of the variable that make the inequality true.
To check if your solution is correct, plug it back into the original inequality and see if it makes the inequality true. If it does, then your solution is correct. If not, double-check your work for any errors.
Common mistakes when solving inequalities include forgetting to flip the inequality symbol when multiplying or dividing both sides by a negative number, not distributing correctly when solving multi-step inequalities, and not checking the solution in the original inequality to make sure it is valid.