1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How to solve this kind of questions ?

  1. Feb 26, 2012 #1
    1. The problem statement, all variables and given/known data
    the question is :
    Get an example of metrics M2X2 that:
    A^2 doest equal A but A^3 equals A^2

    3. The attempt at a solution
    I tried to put matrices A equals :
    a b
    c d

    and tried to solve it , but I get to 4 equations with 4 parameters and I don't know how to solve it , is there any easier way ?
     
  2. jcsd
  3. Feb 26, 2012 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    "Metrics"? Do you mean matrix?

    If [itex]A^3= A^2[/itex] then [itex]A^3- A^2= A(A^2- A)= 0[/itex].
    The requirement that [itex]A^2\ne A[/itex] means that [itex]A^2- A\ne 0[/itex]. Now, it does NOT follow that A= 0 ([itex]0^2= 0[/itex] so A= 0 is not a solution)- the ring of matrices has "0 divisors" But that does mean that A cannot be invertible.
     
  4. Feb 26, 2012 #3
    yes i ment matrix

    i didnt get what u mean by :
    "the ring of matrices has "0 divisors""
     
  5. Feb 26, 2012 #4

    kai_sikorski

    User Avatar
    Gold Member

    First prove that both requirements can't be satisfied by a non-singular matrix.

    Once you know that A is singular, for a 2x2 this means that one of the columns is a scalar multiple of the other. So A will be of the form

    [tex]A = \left(
    \begin{array}{cc}
    a & \kappa b \\
    a & \kappa b \\
    \end{array}
    \right)[/tex]

    EDIT: not sure why the LaTeX isn't working. The matrix should be
    (a) (κ a)
    (b) (κ b)


    Using this assumption calculate A^3-A^2. If this quantity is 0, then in particular the (1,1) component must be 0. This gives you a polynomial which you can solve for a in terms of b (treat [itex]\kappa[/itex] as a parameter). You'll have up to 3 solutions since the polynomial can be at most cubic. Just plug them in and see if any satisfy all the requirements. If so you have your example (in fact you have a family of examples since κ can probably be almost anything), if not you've basically proven that an example doesn't exist for 2x2 matrices.
     
    Last edited: Feb 26, 2012
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook