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How to solve

  1. Mar 25, 2007 #1
    Does anyone know how you would go about solving:

    a + b*x + x^(-y) + c*x^(-2y) + d*x^(1-2y)=0

    solving for x?
  2. jcsd
  3. Mar 26, 2007 #2
    can you give more information, on whad do a, b, c, d, x and y represent. Are some of them variables,functions, series, or merely constants?
    maybe this information would be helpful to me, and to others also who have more expertise.
  4. Mar 26, 2007 #3


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    Sure. It's real easy.

    a = -b*x - x^(-y) - c*x^(-2y) - d*x^(1-2y)

    If that's not the answer you were expecting then how about specifying which variable you want to solve for.
    Last edited: Mar 26, 2007
  5. Mar 26, 2007 #4
    I think he did.

    From OP

  6. Mar 26, 2007 #5
    i guess natski already stated that he wants to solve for x.
  7. Mar 26, 2007 #6


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    Whoops, that will teach me to read all of the post and not skip the last line.

    Sorry, that'ss a transcendental equation in x, so there will be no closed form solution.
    Last edited: Mar 26, 2007
  8. Mar 26, 2007 #7
    ej uart how do u determine wheather it is transcendental equation in x?
  9. Mar 26, 2007 #8


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    Oh yeah it's not transcendental in x. If y is an integer it's a polynomial in x.
  10. Mar 26, 2007 #9
    Um well y is a constant but a,b,c,d are functions of say z. So I want x=function of z or a function of a,b,c,d in this case. I tried to solve numerically for lots of different values of z, plot it and then fit a function to the plot. This worked except for my answer didn't agree with what it should. So I was hoping for a neater algebraic solution.
  11. Mar 27, 2007 #10


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    Well there might be some partiucular values of "y" for which it can work, but in general I don't think it's going to be possible.
    Last edited: Mar 27, 2007
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