# How to solve

Does anyone know how you would go about solving:

a + b*x + x^(-y) + c*x^(-2y) + d*x^(1-2y)=0

solving for x?

## Answers and Replies

can you give more information, on whad do a, b, c, d, x and y represent. Are some of them variables,functions, series, or merely constants?
maybe this information would be helpful to me, and to others also who have more expertise.

uart
Science Advisor
Does anyone know how you would go about solving:

a + b*x + x^(-y) + c*x^(-2y) + d*x^(1-2y)=0

solving for x?

Sure. It's real easy.

a = -b*x - x^(-y) - c*x^(-2y) - d*x^(1-2y)

If that's not the answer you were expecting then how about specifying which variable you want to solve for.

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I think he did.

From OP

solving for x?

Does anyone know how you would go about solving:

a + b*x + x^(-y) + c*x^(-2y) + d*x^(1-2y)=0

solving for x?

i guess natski already stated that he wants to solve for x.

uart
Science Advisor
solving for x?

Whoops, that will teach me to read all of the post and not skip the last line.

Sorry, that'ss a transcendental equation in x, so there will be no closed form solution.

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ej uart how do u determine wheather it is transcendental equation in x?

uart
Science Advisor
ej uart how do u determine wheather it is transcendental equation in x?

Oh yeah it's not transcendental in x. If y is an integer it's a polynomial in x.

Um well y is a constant but a,b,c,d are functions of say z. So I want x=function of z or a function of a,b,c,d in this case. I tried to solve numerically for lots of different values of z, plot it and then fit a function to the plot. This worked except for my answer didn't agree with what it should. So I was hoping for a neater algebraic solution.

uart
Science Advisor
So I was hoping for a neater algebraic solution.

Well there might be some partiucular values of "y" for which it can work, but in general I don't think it's going to be possible.

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