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what we would do is for example 2 points (13,1) (6, 1.4):

[tex]n=\frac{y_2}{y_1}=(\frac{x_2}{x_1})^n[/tex]

[tex]n=\frac{6}{13}=(\frac{1.4}{1})^n[/tex]

so:

[tex]~0.46=1.4^?[/tex]

we'd have to use trial and error....wat id like to know is how to use logarithm to solve this, he said he might teach it but i was wondering if u guys could fill me in on how to solve this using log:

[tex]~0.46=1.4^n[/tex],

the answer for n is about -2.3...

thanks in advance