f(x) continues in [a,b] interval,and differentiable (a,b) b>a>0(adsbygoogle = window.adsbygoogle || []).push({});

alpha differs 0

proove that there is b>c>a

in that formula:

http://img392.imageshack.us/my.php?image=81208753je3.gif

my trial:

i mark alpha as "&"

mean theorim says f'(c)=[(f(b)-f(a)]/(b-a)

[f(b)*(a^&) - f(a)*b^&] / [a^& - b^&]= f(c) -c * [(f(b)-f(a)]/[(b-a) * &]

using mean theorem i replaced f'(c)

what should i do next??

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: How to use mean theorem to solve this proof

**Physics Forums | Science Articles, Homework Help, Discussion**