# How to write this logarithmic equation as a power

brandon26
how can the relationship between y and x in the form Iny = 3+0.2x, be written in the form y = pq^x.

I tried many ways, but can't find the righ format, someone help please?

mantito
1) ln(a)=x means a=exp(x)
2) exp(x+y)=exp(x)*exp(y)

brandon26
yes, but that doesn't help me?

mantito
1)lny=3+0.2x => y=exp(3+0.2x). Now you do the 2).

brandon26
Oh right. Thank you. I got y=exp(3) * exp (0.2x).
That becomes y = exp(3+0.6) * exp(x)

brandon26
Sorry that is wrong

brandon26
y = exp(0.2)x + exp(3). is that right?

mantito
sorry, i forgot this one:)
3)a^(b*c)=(a^b)^c

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