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How would I integrate?

  1. Jun 7, 2013 #1
    1. The problem statement, all variables and given/known data

    integrate 2t^(2)/(1+t^2)^(2)

    2. Relevant equations

    trig sub 1+tan^2(x)= sec^2(x)

    3. The attempt at a solution
    the attempted solution is attached.
     

    Attached Files:

  2. jcsd
  3. Jun 7, 2013 #2

    ehild

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    Your derivation is not correct and the method you follow is a bit complicated. Try integration by parts, ∫u'vdt=uv-∫uv'dt, with u'=2t/(1+t^2)^2 and v=t.

    ehild
     
    Last edited: Jun 8, 2013
  4. Jun 7, 2013 #3

    SteamKing

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    If y = (1/3)t + C, then dy/dt = 1/3, which is clearly not even remotely close to the original integrand.
     
  5. Jun 8, 2013 #4
    omg! i knowwwwwwwwwwwwwwwwww! i did it. that was so stupid of me. thank you.
     
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