1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How would I solve this derivative?

  1. Oct 25, 2011 #1
    f(x) = xe2x, x ε ℝ And determine the domain.

    So I did...

    f'(x) = xe2x [itex]\bullet[/itex] d/dx 2

    I applied the chain rule. I'm not sure if I did this right.
     
  2. jcsd
  3. Oct 25, 2011 #2
    you'll have to use the product rule AND the chain rule
     
  4. Oct 25, 2011 #3
    Ahh I see thank you
     
  5. Oct 25, 2011 #4

    Mark44

    Staff: Mentor

    And in that order.
     
  6. Oct 25, 2011 #5
    Okay cool!
     
  7. Oct 25, 2011 #6
    So I applied the product rule 1st;

    f(x) = xe2x
    f'(x) = xe(2x) + xe(2)

    Did I do this correctly?
     
  8. Oct 25, 2011 #7
    Not correct:

    First, what is the derivative of e^(2x) ?

    Second, if f and g are arbitrary functions of x, what is the derivative of f*g with respect to x (ie, what does the product rule say)?
     
  9. Oct 25, 2011 #8
    derivative of e2x is 2e?
     
  10. Oct 25, 2011 #9
    Nope !

    Here we have to use the chain rule but before we get there, what is the derivative of e^(x)?
     
  11. Oct 25, 2011 #10
    Just ex

    So...

    e2x = 2ex ?
     
  12. Oct 25, 2011 #11
    Close but you are missing one thing.

    Maybe if you saw another example it would become more clear...
    What is the derivative of sin(2x)?

    Or if you prefer by the definition of the chain rule:
    [itex](f \circ g)' = f'(g) * g'[/itex]

    In your case, what is f and what is g?
    Then can you see your mistake?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: How would I solve this derivative?
Loading...