- #1
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How would you solve this Related Rates problem?
- MHB
- Thread starter zimsam
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- Related rates
Answers and Replies
- #2
- 1,103
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(a) $\dfrac{d}{dt}\bigg[(x-1)^2+ 2y^2=2 \bigg]$
you are given $\dfrac{dx}{dt}$ and the position of the planet.
use the derivative to calculate $\dfrac{dy}{dt}$
(b) hint …
$\theta = \arctan\left(\dfrac{y}{x}\right)$
you are given $\dfrac{dx}{dt}$ and the position of the planet.
use the derivative to calculate $\dfrac{dy}{dt}$
(b) hint …
$\theta = \arctan\left(\dfrac{y}{x}\right)$
- #3
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When I find dy/dt, it comes out to =0 for me. dy/dx=(-dx/dt(x-1))/2y. Surely the rate of change of y is not zero...
- #4
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- #5
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I already know that dy/dt must be changing as well...
How did I make a mistake in my implicit differentiation?
- #6
- 1,103
- 1
you didn’t make a mistake …
dy/dt = 0 at (1,1) which is at the endpoint of the minor axis
y is changing from increasing to decreasing w/respect to time at that position