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How would you you derive the (ms/3) correction factor for calculating natural freq

  1. Jan 28, 2013 #1
    1. The problem statement, all variables and given/known data

    In general, I know that you can use the equation ωn=[k/m]^0.5 to calculate the natural frequency of a hanging spring and mass system.

    However, for a non-ideal spring (where the mass of the spring isn't negligible) a correction factor is added to the equation and it becomes:

    ωn=[k/(m+ms/3)]^0.5

    where k is the spring constant, m is the mass of the hanging mass, and ms is the mass of the spring.

    How would you derive the ms/3 correction factor in this equation? I'm trying to prove that the equation is viable.

    Thanks!
     
  2. jcsd
  3. Jan 30, 2013 #2

    rude man

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