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Physics
High Energy, Nuclear, Particle Physics
HQET Feynman Rule: QCD Interaction Vertex Explained
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[QUOTE="Elmo, post: 6609616, member: 686852"] [B]TL;DR Summary:[/B] A slight confusion about HQET Feynman rules ,as stated in most texts. Several texts state the vertex HQET Feynman rule as : igT[SUB]ij[/SUB]v[SUP]μ[/SUP]\frac{1}{1+\slashed{v}} with the reasoning for v[SUB]μ[/SUB] presented as being due to the QCD interaction vertex being between two heavy quark propagators, which are \frac{1+\slashed{v}}{2v.k}, giving : v[SUP]μ[/SUP]\frac{1+\slashed{v}}{2}=\frac{1+\slashed{v}}{2}γ[SUP]μ[/SUP]\frac{1+\slashed{v}}{2}. So in general, shouldn't the vertex rule be the same as in QCD ? The only difference being the heavy quark propagator. [/QUOTE]
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High Energy, Nuclear, Particle Physics
HQET Feynman Rule: QCD Interaction Vertex Explained
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