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Hwk. Problem:Gravitational Potential Energy

  1. Oct 12, 2004 #1
    A 70.0 kg skier rides a 2860 m long lift to the top of a mountain. The lift makes an angle of 14.8° with the horizontal. What is the change in the skier's gravitational potential energy?

    Would I use the equation: PE= (mg*final height) - (mg*initial height)? What do I do with the 14.8degrees? Please help. I'm stuck.
     
  2. jcsd
  3. Oct 12, 2004 #2

    chroot

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    Potential energy does not have anything to do with angles. All that matters is the change in altitude. The angle was provided specifically to confuse you.

    - Warren
     
  4. Oct 12, 2004 #3
    Problem: Gravitational Potential Energy

    if the 14.8 degrees is useless, what would i have to do to solve the problem. I don't get it????
     
  5. Oct 12, 2004 #4

    chroot

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    The change in gravitational potential energy when moving a mass m through a height h is just

    [tex]\Delta PE = m g \Delta h[/tex]

    - Warren
     
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