# Hwk. Problem:Gravitational Potential Energy

1. Oct 12, 2004

### shawonna23

A 70.0 kg skier rides a 2860 m long lift to the top of a mountain. The lift makes an angle of 14.8° with the horizontal. What is the change in the skier's gravitational potential energy?

Would I use the equation: PE= (mg*final height) - (mg*initial height)? What do I do with the 14.8degrees? Please help. I'm stuck.

2. Oct 12, 2004

### chroot

Staff Emeritus
Potential energy does not have anything to do with angles. All that matters is the change in altitude. The angle was provided specifically to confuse you.

- Warren

3. Oct 12, 2004

### shawonna23

Problem: Gravitational Potential Energy

if the 14.8 degrees is useless, what would i have to do to solve the problem. I don't get it????

4. Oct 12, 2004

### chroot

Staff Emeritus
The change in gravitational potential energy when moving a mass m through a height h is just

$$\Delta PE = m g \Delta h$$

- Warren