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Hydr. force on a triang. tank (force one end & pumping out)
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[QUOTE="SteamKing, post: 4944595, member: 301881"] That's OK. g is usually taken as 32.2 ft/s[SUP]2[/SUP] in the imperial units. If you are calculating work, then you must have units for work (force * distance, eh?) Going back to your derivation of the hydrostatic force, you used the depth as (3 - y) and the width wi as (3 - 2y/3). When y = 3 feet, the depth is zero, but wi must be 2 feet, the width of the trough at the top. Similarly, when y = 0, wi must be zero, since we are at the bottom of the trough. [/QUOTE]
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Hydr. force on a triang. tank (force one end & pumping out)
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