# Hydraulic force

Most examples of hydraulic mechanical advantage display a little force on a small piston traveling a long distance to move a bigger piston a short distance with a lot of force.

With the inverse, if we have an input of:
100 lbs of force on a 3" diameter piston traveling 1"
the output would be
33 lbs of force on a 1" diameter piston traveling 3"
and this is true for single pistons.

What happens if the output is forked into 2 or more pistons as my illustration shows?
To have the same travel & force on the small diameter output pistons, would the travel & force on the input piston need to change at all? Or will it stay the same (as with a single output cylinder)?

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CWatters
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With the inverse, if we have an input of:
100 lbs of force on a 3" diameter piston traveling 1"
the output would be
33 lbs of force on a 1" diameter piston traveling 3"

100lbs on a 3" diameter piston is 14psi
33lbs on a 1" diameter piston is 38psi

You can't use just the diameter of the pistons. You have to calculate the area of each piston.

Piston A = 3 square inches
Piston B = 1 square inch

Applying force to Piston A to move it 1 inch will move Piston B 3 inches, with 1/3rd the output force.
Applying force to Piston B to move it 3 inches will move Piston A 1 inch, with 3 times the output force.