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A hydraulic lift has two connected pistons with cross-sectional

areas 25 cm2 and 430 cm2. It is filled with oil of density 500 kg/m3.

a) What mass must be placed on the small piston to support a car of mass 1300 kg at equal fluid levels? (answer: 75.58kg)

b) With the lift in balance with equal fluid levels, a person of mass 60 kg gets into the car. What is the equilibrium height difference in the fluid levels in the pistons? (Answer= 2.8m)

c) How much did the height of the car drop when the person got in the car? ????

please help. my rationale thus far is that volume is conserved. could anyone direct me in applying the right concept? thanks.