1. The problem statement, all variables and given/known data A hydraulic lift has two connected pistons with cross-sectional areas 25 cm2 and 250 cm2. It is filled with oil of density 510 kg/m3. a) What mass must be placed on the small piston to support a car of mass 1200 kg at equal fluid levels? I got this answer - 120 kg b) With the lift in balance with equal fluid levels, a person of mass 90 kg gets into the car. What is the equilibrium height difference in the fluid levels in the pistons? i got this answer 7.0588m c) How much did the height of the car drop when the person got in the car? HELP: The fluid is incompressible, so volume is conserved. HELP: Remember, one side will go up and one side will go down. The difference you calculated in part (b) was the sum of those two changes. C is the part that i am very confused on. I thought i was doing it correct and apparently not. 2. Relevant equations h1+h2 = 7.0588 I thought this was the equation i used to figure out part C but i am just lost on it. 3. The attempt at a solution above.