A hydraulic lift is used to jack a 970 kg car .12m off the floor. The diameter of the output piston is .18 m, and the input force is 270 N.
If the input piston moves .13 m in each stroke, how high does the car move up for each stroke?
2-3. Relevant equations and attempt at solving
That becomes pghA=pghA
p = density
So I get 270=p(9.8)(.13)(A) which is the input force.
I could set that equal to the output force:
.02545 is the area of a circle when I plug in .09 for radius.
The p's would cancel, and I'm left with the variables A1 and h2.
I know I can use the system of equations to solve this, but I want to know if I set up the equations correctly. And also, what do I do with the .12 m (that the car is lifted off the ground)??