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Hello All,
pls see picture , input force F1 and area A1 and second area A2 are all same for 3 cases
for the 1st case , output force F2 should be F2=A2/A1 x F1 , by pascal's principle ,
what about output forces of F3 and F4 ? can be same as F2 ? how i calculate them ?
Hydraulic pressure applies on all the inner surfaces, upper, base and the sides of A2. Some forces by pressure cancel because they have opposite directions and you would get the net results.
The "moving areas" are the only ones to be considered.
The force on the top surfaces A2 of cases 2 and 3 produces no movement; therefore, no mechanical work.
The "moving areas" are the only ones to be considered.
The force on the top surfaces A2 of cases 2 and 3 produces no movement; therefore, no mechanical work.
Presumably the red open outline represents a free-to-move piston. Why wouldn't the piston move?
Hello All,
pls see picture , input force F1 and area A1 and second area A2 are all same for 3 cases
for the 1st case , output force F2 should be F2=A2/A1 x F1 , by pascal's principle ,
what about output forces of F3 and F4 ? can be same as F2 ? how i calculate them ?
thanks
Please re-post this in the Homework Help, Introductory Physics forum and use the hints you have been given here to show your work toward a solution. This misplaced schoolwork thread is now locked.
